Quiz: Differentiability
Test your understanding of differentiability with these review questions.
1. If a function is differentiable at a point, it must also be:
- Increasing at that point
- Continuous at that point
- Defined on all real numbers
- Equal to zero at that point
Show Answer
The correct answer is B. Differentiability implies continuity—if f'(a) exists, then f must be continuous at a. This is a fundamental theorem in calculus. The converse is false: continuity does not imply differentiability.
Concept Tested: Differentiability Implies Continuity
2. Which of the following is NOT a point where a function can fail to be differentiable?
- A corner point
- A cusp
- A point where the function is continuous and smooth
- A vertical tangent
Show Answer
The correct answer is C. If a function is continuous and smooth (no sharp features) at a point, it's differentiable there. Corners, cusps, and vertical tangents all prevent differentiability.
Concept Tested: Non-Differentiable Points
3. The function f(x) = |x| is not differentiable at x = 0 because:
- It is not continuous at x = 0
- It has a corner (left and right derivatives differ)
- It has a vertical tangent
- It approaches infinity
Show Answer
The correct answer is B. At x = 0, the left derivative is −1 and the right derivative is +1. Since these one-sided derivatives are different, the derivative doesn't exist at x = 0. This creates a corner or "V" shape.
Concept Tested: Corner Point
4. The function f(x) = x^(2/3) has what type of non-differentiable point at x = 0?
- Corner
- Jump discontinuity
- Cusp
- Removable discontinuity
Show Answer
The correct answer is C. At x = 0, the function f(x) = x^(2/3) has a cusp—the curve comes to a sharp point where the derivative approaches ±∞ from both sides. The tangent line would be vertical.
Concept Tested: Cusp
5. If a function has a vertical tangent at x = a, which statement is true?
- f(a) is undefined
- f'(a) = 0
- f'(a) does not exist (approaches ±∞)
- The function is discontinuous at x = a
Show Answer
The correct answer is C. A vertical tangent means the slope is infinite (undefined). The derivative doesn't exist at that point, but the function itself is continuous there. The curve is so steep it's vertical.
Concept Tested: Vertical Tangent Point
6. Which statement about the relationship between continuity and differentiability is correct?
- If a function is continuous, it must be differentiable
- If a function is differentiable, it might not be continuous
- Continuity is necessary but not sufficient for differentiability
- Differentiability is necessary for continuity
Show Answer
The correct answer is C. Continuity is necessary (differentiable implies continuous) but not sufficient (continuous doesn't imply differentiable). A function must be continuous to be differentiable, but continuity alone doesn't guarantee differentiability.
Concept Tested: Continuous Not Implies Differentiable
7. What can you conclude if the left-hand derivative and right-hand derivative at x = a are equal?
- The function is continuous at x = a
- The function is differentiable at x = a
- The function has a corner at x = a
- The limit exists at x = a
Show Answer
The correct answer is B. When both one-sided derivatives exist and are equal, the (two-sided) derivative exists at that point. This is the definition of differentiability at a point.
Concept Tested: One-Sided Derivative
8. The principle of local linearity means that:
- All functions are linear
- Differentiable functions look like straight lines when zoomed in sufficiently
- The derivative is always constant
- Linear functions are the only differentiable functions
Show Answer
The correct answer is B. Local linearity means that if you zoom in far enough on a differentiable function at any point, the graph will look like a straight line—its tangent line. This is why linear approximation works.
Concept Tested: Local Linearity
9. For the piecewise function f(x) = {x² if x ≤ 1; 2x−1 if x > 1}, is f differentiable at x = 1?
- Yes, because both pieces are differentiable
- Yes, because the function is continuous at x = 1
- No, because the left and right derivatives are different
- No, because piecewise functions are never differentiable
Show Answer
The correct answer is C. Left derivative at x = 1: d/dx(x²) = 2x = 2. Right derivative at x = 1: d/dx(2x−1) = 2. Both equal 2! Check continuity: both give f(1) = 1. Actually, f IS differentiable at x = 1. Let me reconsider...
The correct answer is A (or we need to verify). Left: f'(1⁻) = 2(1) = 2. Right: f'(1⁺) = 2. They match! And f(1) = 1 from left, 2(1)−1 = 1 from right. So f is continuous and differentiable.
Concept Tested: Differentiability at a Point
10. Where is f(x) = √(x − 2) differentiable?
- All real numbers
- x > 2 only
- x ≥ 2
- x < 2 only
Show Answer
The correct answer is B. The function f(x) = √(x − 2) is defined for x ≥ 2, but it has a vertical tangent at x = 2 (derivative approaches infinity). It's differentiable only for x > 2, where f'(x) = 1/(2√(x−2)).
Concept Tested: Differentiable Function