Quiz: Related Rates and Linear Approximation
Test your understanding of related rates and linear approximation with these review questions.
1. Related rates problems involve:
- Rates that have no connection
- Quantities that change with respect to a common variable (usually time)
- Only constant rates
- Rates that are always equal
Show Answer
The correct answer is B. Related rates problems involve multiple quantities that change with respect to a common variable, typically time. An equation relates the quantities, and implicit differentiation relates their rates.
Concept Tested: Related Rates
2. The first step in solving a related rates problem is:
- Differentiate immediately
- Draw a diagram and identify all variables and given rates
- Solve for the unknown variable
- Plug in numbers
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The correct answer is B. Always start by drawing a diagram, labeling variables, and identifying what rates are given and what rate you need to find. Then find an equation relating the quantities.
Concept Tested: Related Rates Setup
3. A ladder 10 ft long leans against a wall. If the bottom slides away at 2 ft/sec, how fast is the top sliding down when the bottom is 6 ft from the wall?
- 1.5 ft/sec
- 2 ft/sec
- 2.5 ft/sec
- 3 ft/sec
Show Answer
The correct answer is A. Use x² + y² = 100. Differentiate: 2x(dx/dt) + 2y(dy/dt) = 0. When x = 6, y = 8. So 2(6)(2) + 2(8)(dy/dt) = 0, giving dy/dt = −1.5 ft/sec (negative means sliding down).
Concept Tested: Ladder Problem
4. The linear approximation formula is:
- f(x) ≈ f(a) + f'(a)(x − a)
- f(x) ≈ f(a) + f''(a)(x − a)
- f(x) ≈ f'(a)(x − a)
- f(x) ≈ f(a)f'(x)
Show Answer
The correct answer is A. Linear approximation (tangent line approximation): L(x) = f(a) + f'(a)(x − a). This approximates f(x) near x = a using the tangent line at a.
Concept Tested: Linearization Formula
5. Using linear approximation, estimate √4.1 given that √4 = 2.
- 2.01
- 2.025
- 2.05
- 2.1
Show Answer
The correct answer is B. Let f(x) = √x, a = 4. f'(x) = 1/(2√x), f'(4) = 1/4. L(4.1) = 2 + (1/4)(0.1) = 2 + 0.025 = 2.025.
Concept Tested: Tangent Line Approximation
6. What is the differential dy if y = x³?
- dy = 3x²
- dy = 3x² dx
- dy = x³ dx
- dy = 3x dx
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The correct answer is B. The differential dy = f'(x) dx. For y = x³, dy = 3x² dx. This represents the change in y along the tangent line for a small change dx in x.
Concept Tested: Differential
7. A spherical balloon is inflated so that its radius increases at 3 cm/sec. How fast is the volume increasing when r = 10 cm?
- 400π cm³/sec
- 1200π cm³/sec
- 4000π cm³/sec
- 1200 cm³/sec
Show Answer
The correct answer is B. V = (4/3)πr³. Differentiate: dV/dt = 4πr²(dr/dt). When r = 10, dr/dt = 3: dV/dt = 4π(100)(3) = 1200π cm³/sec.
Concept Tested: Balloon Problem
8. The error in linear approximation is generally smaller when:
- x is far from a
- x is close to a
- f'(a) is large
- f(a) is large
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The correct answer is B. Linear approximation is most accurate when x is close to the center point a. The error grows as we move away from a, especially when the function has large curvature.
Concept Tested: Error in Approximation
9. A 5-foot tall person walks away from a 20-foot lamppost at 4 ft/sec. How fast is their shadow lengthening?
- 1 ft/sec
- 4/3 ft/sec
- 3 ft/sec
- 4 ft/sec
Show Answer
The correct answer is B. Using similar triangles: 20/(x+s) = 5/s, giving 20s = 5x + 5s, so s = x/3. Differentiate: ds/dt = (1/3)(dx/dt) = (1/3)(4) = 4/3 ft/sec.
Concept Tested: Shadow Problem
10. If dy = f'(x) dx, what does dy represent geometrically?
- The actual change in y
- The change in y along the tangent line
- The slope of the curve
- The area under the curve
Show Answer
The correct answer is B. The differential dy represents the change in y along the tangent line (linear approximation) for a change dx in x. It approximates but doesn't equal the actual change Δy.
Concept Tested: dy Notation