Implicit Differentiation Steps
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Description
This MicroSim walks you through the implicit differentiation process step by step, making each algebraic manipulation visible and clear. When an equation involves both x and y but y is not explicitly solved for (like x^2 + y^2 = 25, a circle), we use implicit differentiation to find dy/dx.
The Key Insight
Every time you differentiate a term containing y, you must apply the chain rule. Since y is implicitly a function of x, differentiating y^n gives you n*y^(n-1) * (dy/dx). This extra dy/dx factor is what makes implicit differentiation special.
How to Use
- Choose an equation: Click one of the five preset equation buttons at the bottom
- Step through: Click "Next Step" to see each step of the implicit differentiation process
- Show all at once: Click "Show All" to reveal the complete solution
- Start over: Click "Reset" to return to the first step
Preset Equations
| Equation | Description | Notable Features |
|---|---|---|
| x^2 + y^2 = 25 | Circle | Classic example, simple chain rule |
| x^3 + y^3 = 6xy | Folium of Descartes | Requires product rule on right side |
| xy = 1 | Hyperbola | Product rule application |
| sin(x + y) = y | Transcendental | Chain rule with trig function |
| e^(xy) = x - y | Exponential | Chain rule + product rule nested |
Delta Moment
"Here's the secret to implicit differentiation: whenever I see a y, I think 'that's secretly a function of x!' So when I differentiate y^2, I don't just get 2y. I get 2y times dy/dx, because the chain rule says I need to multiply by the derivative of the inside function. And y is that inside function hiding in plain sight!"
The Implicit Differentiation Algorithm
- Differentiate both sides with respect to x
- Apply the chain rule to every term containing y (multiply by dy/dx)
- Use product rule where needed (for terms like xy)
- Collect all dy/dx terms on one side of the equation
- Factor out dy/dx from all terms
- Solve for dy/dx by dividing both sides
Lesson Plan
Learning Objectives
By the end of this activity, students will be able to:
- Apply the chain rule when differentiating terms containing y (Bloom Level 3)
- Execute the step-by-step process of implicit differentiation (Bloom Level 3)
- Implement algebraic manipulation to isolate dy/dx (Bloom Level 3)
Target Audience
- AP Calculus AB/BC students
- High school students (grades 11-12)
- College students in Calculus I
Prerequisites
- Understanding of the chain rule
- Familiarity with product rule
- Experience with explicit differentiation
- Basic algebraic manipulation skills
Guided Activity: Pattern Recognition (15 minutes)
Warm-up (3 min):
Start with the circle equation x^2 + y^2 = 25. Ask students:
- "Why can't we just solve for y first and then differentiate?"
- "What happens when we try to solve for y?" (Two branches: y = +/- sqrt(25 - x^2))
Exploration (7 min):
- Click through the circle example step by step
- At each step, pause and ask: "What rule are we using here?"
- Emphasize: "Every time we differentiate y, we multiply by dy/dx"
- Show how collecting terms is like solving any equation for a variable
Challenge (5 min):
Move to x^3 + y^3 = 6xy (Folium of Descartes):
- Before clicking, have students predict: "How many dy/dx terms will appear?"
- Work through together, identifying product rule on the right side
- Discuss why factoring is necessary when there are multiple dy/dx terms
Independent Practice
Have students:
- Choose sin(x + y) = y and predict each step before revealing
- Check their predictions against the MicroSim
- Write out the e^(xy) = x - y solution on paper before checking
Assessment Questions
-
When differentiating implicitly, why do we multiply by dy/dx every time we differentiate a y term?
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Given x^2 + xy + y^2 = 7, find dy/dx. (Answer: dy/dx = -(2x + y)/(x + 2y))
-
Why does the equation xy = 1 require the product rule?
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At the point (3, 4) on the circle x^2 + y^2 = 25, what is the slope of the tangent line?
Extension: Connecting to Geometry
After finding dy/dx = -x/y for the circle:
- At point (3, 4), dy/dx = -3/4
- The radius to (3, 4) has slope 4/3
- Notice: (-3/4) * (4/3) = -1 (perpendicular!)
- This proves the tangent line is perpendicular to the radius at every point on a circle.
Why Implicit Differentiation Matters
Many important curves cannot be easily written as y = f(x):
- Circles, ellipses, hyperbolas define y implicitly
- Level curves of functions F(x,y) = c
- Economic equilibrium curves where supply and demand are interrelated
- Related rates problems where multiple variables change together
Implicit differentiation lets us find slopes, rates of change, and tangent lines for all these curves without the need to solve for y explicitly.
References
-
Implicit Differentiation - Khan Academy - Comprehensive review with examples
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Implicit Differentiation - Paul's Online Math Notes - Detailed explanations with worked examples
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p5.js Reference - Documentation for the p5.js library used to create this visualization