The Natural Logarithm as Area
You can include this MicroSim on your website using the following iframe:
1 | |
Description
This MicroSim visualizes one of the most beautiful definitions in calculus: the natural logarithm as the area under the curve y = 1/t. Rather than defining ln(x) as the inverse of e^x (which requires defining e first), we can define:
This means the natural logarithm of any positive number a equals the area under the hyperbola y = 1/t from t = 1 to t = a.
Key Observations
| Value of a | Area = ln(a) | Interpretation |
|---|---|---|
| a = 1 | 0 | No area from 1 to 1 |
| a = e | 1 | This is how e is defined! |
| a > 1 | positive | Area accumulates to the right |
| 0 < a < 1 | negative | "Negative area" going left from 1 |
How to Use
- Drag the slider to move the endpoint a between 0.1 and 10
- Watch the shaded area change as a moves
- Toggle the ln(x) overlay to see how the area corresponds to the logarithm curve
- Click Animate to see a sweep through all values
- Use Quick Jump buttons to snap to special values like 1, e, or 10
Special Points to Explore
- a = 1: The area is zero because we're measuring from 1 to 1
- a = e (approximately 2.718): The area equals exactly 1. This is actually how Euler's number e is defined - it's the value where the area equals 1
- a < 1: When moving left from 1, we accumulate "negative area" (shown in red)
Delta Moment
"So wait - you're telling me ln(3) isn't some magic number? It's just... the area under 1/t from 1 to 3? I can see it? I can measure it? This is the most concrete thing about logs I've ever encountered!"
Why This Matters
This area-based definition gives us:
- A concrete meaning for an abstract function
- A way to prove properties of logarithms geometrically
- The foundation for understanding why \(\frac{d}{dx}[\ln(x)] = \frac{1}{x}\)
- An explanation for why e appears everywhere in calculus
The Connection to the Derivative
By the Fundamental Theorem of Calculus, if we define:
Then differentiating both sides gives us:
This is why the derivative of ln(x) is 1/x - it comes directly from the definition as an integral!
Lesson Plan
Learning Objectives
By the end of this activity, students will be able to:
- Interpret the natural logarithm as an accumulated area
- Explain why ln(1) = 0 and ln(e) = 1
- Visualize the connection between the area definition and the ln function
- Connect this definition to the derivative of ln(x)
Grade Level
High School (AP Calculus AB/BC) and Undergraduate Calculus I
Duration
15-20 minutes for exploration; can be revisited when studying logarithmic differentiation
Prerequisites
Students should be familiar with:
- The concept of area under a curve
- Basic properties of logarithms
- The Fundamental Theorem of Calculus
Activities
Activity 1: Discovering the Pattern (5 minutes)
- Set a = 1 and observe the area is 0
- Slowly increase a to 2, 3, 4, 5
- Record the areas in a table
- Ask: Do these values look familiar? (They're ln(2), ln(3), etc.)
Activity 2: Finding e (5 minutes)
- Challenge: Find the value of a where the area equals exactly 1
- Use the slider to zero in on the answer
- Discuss: This value (approximately 2.718) is called e
- This is one way to DEFINE Euler's number e!
Activity 3: Negative Areas (5 minutes)
- Explore values of a less than 1
- Note the area becomes negative
- Verify that ln(0.5) is approximately -0.693
- Ask: Why does it make sense that ln(a) is negative when 0 < a < 1?
Activity 4: Properties from Pictures (5 minutes)
- Find ln(2) and ln(3) by reading the areas
- Now find ln(6) - is it related to ln(2) + ln(3)?
- Discuss how ln(ab) = ln(a) + ln(b) relates to combining areas
Discussion Questions
- Why is ln(1) = 0? What does this mean geometrically?
- How does this visualization explain why ln(x) grows so slowly for large x?
- If we know the area interpretation, why is it obvious that the derivative of ln(x) is 1/x?
- What would happen if we changed the lower limit from 1 to some other number?
Assessment
Quick Check: Without using a calculator, determine whether each is positive, negative, or zero:
- ln(5) (positive - area from 1 to 5)
- ln(0.2) (negative - going left from 1)
- ln(1) (zero - no area)
- ln(e^2) (should be 2)
Exit Ticket: Explain in your own words why this area interpretation means that \(\frac{d}{dx}[\ln(x)] = \frac{1}{x}\).
Common Misconceptions to Address
| Misconception | Clarification |
|---|---|
| "ln is just the inverse of e^x" | While true, the area definition is more fundamental and explains WHY this inverse relationship exists |
| "The area can't be negative" | We define negative area when integrating "backwards" (from larger to smaller bounds) |
| "e is defined as 2.718..." | Actually, e is defined as the number where the area equals 1. The decimal is a consequence. |
References
-
Area Definition of ln(x) - Paul's Online Math Notes - Detailed explanation of this approach
-
The Natural Logarithm as an Integral - Khan Academy - Video explanations
-
p5.js Reference - Documentation for the p5.js library used in this visualization