Quiz: System Properties and Analysis
Test your understanding of fundamental system properties and analysis techniques.
1. What mathematical condition defines a linear system?
- \(\mathcal{T}[ax_1(t) + bx_2(t)] = a\mathcal{T}[x_1(t)] + b\mathcal{T}[x_2(t)]\) for any inputs and constants
- \(\mathcal{T}[x(t - t_0)] = y(t - t_0)\) for all time shifts
- \(y(t_0)\) depends only on \(x(t)\) for \(t \leq t_0\)
- \(|x(t)| < M_x\) implies \(|y(t)| < M_y\)
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The correct answer is A. A system is linear if it satisfies the superposition principle: \(\mathcal{T}[ax_1(t) + bx_2(t)] = a\mathcal{T}[x_1(t)] + b\mathcal{T}[x_2(t)]\) for any inputs \(x_1(t)\) and \(x_2(t)\) and any constants \(a\) and \(b\). This encompasses both additivity and homogeneity properties. Option B describes time-invariance, option C describes causality, and option D describes BIBO stability.
Concept Tested: Linear Systems
See: Linear Systems
2. For a time-invariant system, if \(y(t) = \mathcal{T}[x(t)]\), what must be true?
- The system parameters change linearly with time
- The system response depends on when the input is applied
- \(\mathcal{T}[x(t - t_0)] = y(t - t_0)\) for all signals and time shifts
- The system has no memory of past inputs
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The correct answer is C. A time-invariant system satisfies \(\mathcal{T}[x(t - t_0)] = y(t - t_0)\) for all signals \(x(t)\) and all time shifts \(t_0\). This means a time shift in the input produces an equivalent time shift in the output with no change in the waveform. Time-invariant systems have constant parameters that do not change over time, ensuring consistent behavior regardless of when an input is applied.
Concept Tested: Time-Invariant Systems
3. What is the BIBO stability condition for an LTI system in terms of its impulse response \(h(t)\)?
- \(h(t) = 0\) for \(t < 0\)
- \(h(t)\) must be a finite-duration signal
- \(\int_{-\infty}^{\infty} |h(t)| dt < \infty\)
- \(h(t)\) must be a periodic function
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The correct answer is C. For LTI systems, BIBO stability requires that the impulse response be absolutely integrable: \(\int_{-\infty}^{\infty} |h(t)| dt < \infty\). This ensures that every bounded input produces a bounded output. Option A describes causality (not stability), option B is too restrictive (stable systems can have infinite-duration impulse responses if they decay sufficiently), and option D is incorrect as impulse responses are generally not periodic.
Concept Tested: Stability, Impulse Response
See: Stability
4. Which of the following best describes a causal system?
- A system whose impulse response \(h(t) = 0\) for \(t < 0\)
- A system that can predict future input values
- A system with zero phase shift at all frequencies
- A system that produces outputs before inputs are applied
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The correct answer is A. A causal system has an impulse response that satisfies \(h(t) = 0\) for \(t < 0\), meaning the output at any time depends only on present and past input values, never on future inputs. All physical systems that operate in real-time must be causal, as they cannot respond to inputs that have not yet occurred.
Concept Tested: Causality, Impulse Response
See: Causality
5. What is the relationship between the step response \(s(t)\) and the impulse response \(h(t)\) for an LTI system?
- \(s(t) = \frac{d}{dt}h(t)\)
- \(s(t) = \int_{-\infty}^{t} h(\tau) d\tau\)
- \(s(t) = h(t) * u(t)\), which is the same as option B
- Both B and C are correct
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The correct answer is D. The step response is the integral of the impulse response: \(s(t) = \int_{-\infty}^{t} h(\tau) d\tau\). This can also be expressed as the convolution of the impulse response with the unit step: \(s(t) = h(t) * u(t)\). Both formulations are equivalent and correct. The step response reveals important characteristics including rise time, settling time, overshoot, and steady-state error.
Concept Tested: Step Response, Impulse Response
See: Step Response
6. How is the frequency response \(H(f)\) of an LTI system related to its impulse response \(h(t)\)?
- \(H(f)\) is the Laplace transform of \(h(t)\)
- \(H(f)\) is the derivative of \(h(t)\)
- \(H(f)\) is the Fourier transform of \(h(t)\): \(H(f) = \int_{-\infty}^{\infty} h(t)e^{-j2\pi ft} dt\)
- \(H(f)\) is the time-reversed version of \(h(t)\)
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The correct answer is C. The frequency response is the Fourier transform of the impulse response: \(H(f) = \int_{-\infty}^{\infty} h(t)e^{-j2\pi ft} dt\). The magnitude \(|H(f)|\) shows how the system amplifies or attenuates different frequencies, while the phase \(\angle H(f)\) shows how the system delays sinusoidal components. Note that option A describes the transfer function \(H(s)\), which is the Laplace transform.
Concept Tested: Frequency Response, Impulse Response
See: Frequency Response
7. What is the impulse response of a memoryless system?
- \(h(t) = K\delta(t)\) where \(K\) is a constant gain
- \(h(t) = u(t)\) (unit step function)
- \(h(t) = e^{-at}u(t)\) (exponential decay)
- \(h(t)\) extends over infinite time
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The correct answer is A. A memoryless system produces outputs that depend only on the current input value, with no dependence on past or future inputs. The impulse response is \(h(t) = K\delta(t)\) where \(K\) is a constant gain. Options B and C describe systems with memory, as their impulse responses extend over time beyond \(t = 0\).
Concept Tested: Memoryless Systems, Impulse Response
See: Memoryless Systems
8. Given two LTI systems connected in series (cascade) with transfer functions \(H_1(s)\) and \(H_2(s)\), what is the overall transfer function?
- \(H_{total}(s) = H_1(s) + H_2(s)\)
- \(H_{total}(s) = H_1(s) \cdot H_2(s)\)
- \(H_{total}(s) = \frac{H_1(s)}{1 + H_1(s)H_2(s)}\)
- \(H_{total}(s) = H_1(s) - H_2(s)\)
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The correct answer is B. For LTI systems in cascade (series), the overall transfer function is the product of individual transfer functions: \(H_{total}(s) = H_1(s) \cdot H_2(s)\). In the time domain, this corresponds to the convolution of impulse responses. Option A describes parallel systems, and option C describes a feedback configuration.
Concept Tested: System Interconnections, Transfer Function
9. For a negative feedback system with forward path \(G(s)\) and feedback path \(H(s)\), what is the closed-loop transfer function?
- \(T(s) = G(s) + H(s)\)
- \(T(s) = G(s) \cdot H(s)\)
- \(T(s) = \frac{G(s)}{1 - G(s)H(s)}\)
- \(T(s) = \frac{G(s)}{1 + G(s)H(s)}\)
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The correct answer is D. The closed-loop transfer function for a negative feedback system is \(T(s) = \frac{G(s)}{1 + G(s)H(s)}\). The denominator \(1 + G(s)H(s)\) is called the characteristic equation, and its roots (poles of the closed-loop system) determine stability. Negative feedback provides stability, disturbance rejection, and reduced sensitivity to parameter variations.
Concept Tested: Feedback Systems, Transfer Function
See: Feedback Systems
10. An LTI system has impulse response \(h(t) = e^{at}u(t)\) where \(a > 0\). What can you conclude about this system's stability?
- The system is stable because it has an exponential impulse response
- The system is stable because the impulse response is causal
- The system is unstable because \(\int_{-\infty}^{\infty} |h(t)| dt = \int_{0}^{\infty} e^{at} dt\) diverges when \(a > 0\)
- Stability cannot be determined without knowing the input signal
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The correct answer is C. The system is unstable because with \(a > 0\), the integral \(\int_{-\infty}^{\infty} |h(t)| dt = \int_{0}^{\infty} e^{at} dt\) diverges (approaches infinity). The BIBO stability condition for LTI systems requires the impulse response to be absolutely integrable. A growing exponential violates this condition, meaning bounded inputs can produce unbounded outputs. Note that causality (option B) does not guarantee stability.
Concept Tested: Stability, Impulse Response
See: Stability, Impulse Response