Quiz: Polynomial Functions
Test your understanding of polynomial functions, end behavior, division techniques, and root finding with these review questions.
1. What is the degree of the polynomial \(f(x) = 4x^5 - 2x^3 + 7x^2 - 1\)?
- \(4\)
- \(5\)
- \(3\)
- \(10\)
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The correct answer is B. The degree of a polynomial is the highest power of the variable that appears. Here, \(x^5\) is the highest power, so the degree is \(5\). Option A mistakes the leading coefficient for the degree. The degree tells us important structural information: a degree-\(5\) polynomial can have up to \(5\) real roots and up to \(4\) turning points.
Concept Tested: Degree of a Polynomial
2. Describe the end behavior of \(f(x) = -3x^4 + 2x^2 - 1\) as \(x \to \infty\).
- \(f(x) \to \infty\)
- \(f(x) \to 0\)
- \(f(x) \to -\infty\)
- \(f(x)\) oscillates
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The correct answer is C. The degree is \(4\) (even) and the leading coefficient is \(-3\) (negative). For even degree with negative leading coefficient, both ends of the graph go down, so as \(x \to \infty\), \(f(x) \to -\infty\) (and same as \(x \to -\infty\)). Only the leading term matters for end behavior because it dominates all lower-order terms for large \(|x|\).
Concept Tested: End Behavior
3. The factor theorem states that \((x - c)\) is a factor of \(f(x)\) if and only if:
- \(f(0) = c\)
- \(f(c) = 0\)
- \(f(c) = c\)
- \(f(1) = c\)
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The correct answer is B. The factor theorem says that \((x - c)\) divides \(f(x)\) evenly precisely when \(c\) is a root of \(f\), i.e., \(f(c) = 0\). This is enormously useful: once you find a root by inspection or trial, you can factor out \((x - c)\) and reduce the polynomial's degree, making further factoring easier. The factor theorem is a special case of the remainder theorem.
Concept Tested: Factor Theorem
4. What is the maximum number of turning points a polynomial of degree \(6\) can have?
- \(5\)
- \(6\)
- \(7\)
- \(3\)
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The correct answer is A. A polynomial of degree \(n\) can have at most \(n - 1\) turning points. For degree \(6\): \(6 - 1 = 5\). The actual number can be less, but never more. This "one less than the degree" rule is a direct consequence of calculus (the derivative has one less degree). Use this fact to sanity-check your sketches of polynomial graphs.
Concept Tested: Turning Points Count
5. What is the remainder when \(f(x) = x^3 - 2x^2 + 3x - 5\) is divided by \((x - 2)\)?
- \(-3\)
- \(5\)
- \(1\)
- \(0\)
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The correct answer is C. By the remainder theorem, the remainder when dividing \(f(x)\) by \((x - c)\) is \(f(c)\). Here, \(f(2) = 8 - 8 + 6 - 5 = 1\). Since the remainder is not zero, \((x - 2)\) is not a factor. The remainder theorem is a huge time-saver — you avoid performing the full division just to find the remainder.
Concept Tested: Remainder Theorem
6. For the polynomial \(f(x) = (x - 2)^2(x + 3)\), what happens at \(x = 2\)?
- The graph crosses the \(x\)-axis
- The graph touches the \(x\)-axis and bounces back
- The graph has a vertical asymptote
- The graph has a hole
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The correct answer is B. The factor \((x - 2)^2\) indicates that \(x = 2\) is a root with multiplicity \(2\). Roots with even multiplicity cause the graph to touch the \(x\)-axis and bounce back rather than cross. Roots with odd multiplicity cause crossing. Holes and asymptotes are features of rational functions, not polynomials — polynomials are continuous and smooth everywhere.
Concept Tested: Multiplicity of Roots
7. The roots of \(x^3 + 2x^2 - 5x - 6 = 0\) sum to what value (using the sum of roots formula)?
- \(2\)
- \(6\)
- \(-6\)
- \(-2\)
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The correct answer is D. For a polynomial \(a_n x^n + a_{n-1}x^{n-1} + \cdots\), the sum of roots is \(-\frac{a_{n-1}}{a_n}\). Here \(a_n = 1\) (coefficient of \(x^3\)) and \(a_{n-1} = 2\) (coefficient of \(x^2\)). So the sum is \(-\frac{2}{1} = -2\). This formula lets you find the sum of roots without actually solving the polynomial.
Concept Tested: Sum of Roots Formula
8. Which of the following describes a cubic function?
- Degree \(2\), up to \(1\) turning point
- Degree \(4\), up to \(3\) turning points
- Degree \(3\), up to \(2\) turning points
- Degree \(5\), up to \(4\) turning points
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The correct answer is C. A cubic function has degree \(3\), and by the rule "at most \(n - 1\) turning points," it can have up to \(2\) turning points. Cubics always have at least one real root (the graph must cross the \(x\)-axis at least once because of the opposing end behavior of odd-degree polynomials). Option A describes a quadratic, B describes a quartic, and D describes a quintic.
Concept Tested: Cubic Function
9. Given that \(x = -1\) is a root of \(f(x) = x^3 - 4x^2 + x + 6\), what are the remaining two roots?
- \(x = 2\) and \(x = 3\)
- \(x = -2\) and \(x = 3\)
- \(x = 2\) and \(x = -3\)
- \(x = -2\) and \(x = -3\)
Show Answer
The correct answer is A. First verify: \(f(-1) = -1 - 4 - 1 + 6 = 0\). ✓ Divide \(f(x)\) by \((x + 1)\) using synthetic division with coefficients \([1, -4, 1, 6]\) and \(c = -1\): the quotient is \(x^2 - 5x + 6\). Factor: \((x - 2)(x - 3) = 0\), giving \(x = 2\) and \(x = 3\). So the three roots are \(-1, 2, 3\).
Concept Tested: Polynomial Division
10. What is the leading coefficient of \(f(x) = 5 - 3x + 2x^4 - x^2\)?
- \(5\)
- \(-1\)
- \(-3\)
- \(2\)
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The correct answer is D. The leading coefficient is the coefficient of the highest-power term. First rewrite in standard order: \(f(x) = 2x^4 - x^2 - 3x + 5\). The highest power is \(x^4\), with coefficient \(2\). A common mistake is to pick the first coefficient you see (option A picks the constant term) without rearranging. Always reorder by descending powers first.
Concept Tested: Leading Coefficient